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Home » Business Maths » Profit and Loss

Profit and Loss

Cost Price: The price at which an article is bought or purchased is called its cost price. (C.P.)

Selling Price: The price at which an article is sold is called its selling price. (S.P.)

Profit: When an article is sold for more than what it costs, we say that there is a ‘profit’ or gain.

Loss: When an article is sold for less than what it costs , we say that there is a ‘loss’.

When the selling price is equal to the cost price, then there is neither profit nor loss.

We recall a few important facts below:

  1. Profit = Selling Price – Cost Price
  2. Loss = Cost Price – Selling Price
  3. Cost Price = Selling Price – Profit or, Selling Price + Loss
  4. Selling Price = Cost Price + Profit or, Cost Price – Loss
  5. Profit or Loss per cent = \dfrac{Total \hspace{1mm} profit/loss}{cost \hspace{1mm} price} \times 100

Caution: Profit or loss per cent is never calculated on the number of items sold, but on the cost prices of the items.

In calculating any percentage change, the increase or decrease is expressed as a percentage of the first value. Buying comes before selling , thus, profit or loss is expressed as a percentage of the buying price ( i.e., the cost price ) and not of the selling price.

Overheads – If there are some additional expenses incurred on the transportation , repair etc of an article purchased, they are included in the C.P. of the article and are called ‘overheads’.

3 Major Type of Profit and Loss Problems

Type 1 : Find Profit or Loss Percent.

Example 1: What is the profit per cent if a table bought for Rs \hspace{1mm} 65 is sold for Rs \hspace{1mm} 70 ?

Solution:  A table is bought for Rs \hspace{1mm} 65 and sold for Rs \hspace{1mm} 70 .

Total profit =Rs \hspace{1mm} 70 -Rs \hspace{1mm} 65= Rs \hspace{1mm} 5

Profit % = \dfrac{Profit}{C.P.} \times 100 = \dfrac{100}{13} \%

Example 2: Arun buys a T.V. for Rs \hspace{1mm} 16000 . The transportation charges are Rs \hspace{1mm} 200 and the installation charges are Rs \hspace{1mm} 800 . He then sells it to his friend for Rs \hspace{1mm} 15300 . Find the loss per cent.

Solution: C.P.= Rs \hspace{1mm} 1600 + Rs \hspace{1mm} 200 + Rs \hspace{1mm} 800 = Rs \hspace{1mm} 17000 .

Here transportation and installation charges fall under overhead costs.

S.P. = Rs \hspace{1mm} 15300

Loss=S.P-C.P.=Rs \hspace{1mm} 17000 -Rs \hspace{1mm} 15300= Rs \hspace{1mm} 1700

Loss \% = \dfrac{Loss}{C.P.} \time 100 = \dfrac{1700}{17000} \times 100 \% = 10 \%

More results on S.P. and C.P.:

1. If there is a profit of r\% then,

S.P. = C.P. + Profit = C.P. + r\% \hspace{1mm} of \hspace{1mm} C.P. = C.P. + \dfrac{r}{100} \hspace{1mm} of \hspace{1mm} C.P.

= (1 +\dfrac{r}{100}) of C.P. = \dfrac{(100 + r)}{100} \hspace{1mm} of \hspace{1mm} C.P.

2. If there is a loss of r\% then,

S.P. = C.P. -Loss = C.P. - r\% \hspace{1mm} of \hspace{1mm} C.P. = C.P. - \dfrac{r}{100} \hspace{1mm} of \hspace{1mm} C.P.

= (1 -\dfrac{r}{100}) of C.P. = \dfrac{(100 - r)}{100} \hspace{1mm} of \hspace{1mm} C.P.

From 1 and 2 , we derive that :

3. C.P. = \dfrac{S.P. \times 100}{100 + r} , when there is a profit of r\%

4. C.P. = \dfrac{S.P. \times 100}{100 - r} , when there is a loss of r\%

Type 2 : Find S.P. when C.P. and Profit (or loss) Percent Given

Example 1: A man bought a T.V. set for Rs \: 3500 and he sold it at a profit of 20\% . Find the selling price.

Solution: Let the cost price be Rs \: 100

Then, S.P. at a profit of 20\% = Rs \: 120

When C.P. is Rs \: 100 S.P. is Rs \: 120

Then, When C.P. =Rs \: 3500, S.P. = Rs \: (\dfrac{120}{100} \times 350) = Rs \: 4200

Alternative Method:

S.P. = \dfrac{ 100 + r}{100} \times C.P. where r =20 and C.P. = Rs \: 3500

\therefore = Rs \: (\dfrac{120}{100} \times 3500) = Rs \: 4200

Example 2:  A man buys a cycle for Rs \: 350 and sells it at a loss of 15\% . Find the selling price of the cycle.

Solution: Let the C.P. be Rs \: 100

Then, S.P. at a loss of 15\% = Rs \: 100- (15\% \hspace{1mm} of \hspace{1mm} Rs 100)=Rs \: (100-15)=Rs \: 85

When C.P.= Rs\: 100, S.P. = Rs \: 85

Then, when C.P. =Rs \: 350 , S.P. = Rs \: (\dfrac{85}{100} \times 350) = Rs \: 297.50

Alternative Method:

S.P.=\dfrac{100-r}{100} \times C.P.  where r=15\% loss and C.P.= Rs \: 350

\therefore S.P.=\dfrac{85}{100} \times 350=Rs \: 297.50

Type 3 : Find Cost Price.

Example 1: Find the cost price of an article which is sold at a profit of 8\% for Rs \: 2160 .

Solution: S.P.=Rs \: 2160 , Profit % = 8

If S.P.=Rs \: 108 , then C.P. = Rs \: 100

If S.P.=Re \: 1 , then C.P. = Rs \: \dfrac{100}{108}

If S.P.=Rs \: 2160 , then C.P.= Rs \: (\dfrac{100}{108} \times 2160) = Rs \: 2000

Alternative Method:

C.P. = \dfrac {S.P. \times 100}{100+r} where r =8, S.P. =Rs \: 2160

\therefore C.P.=\dfrac{Rs \: (2160 \times 100)}{108}=Rs \: 2000

A few harder problems on profit and loss:

Example 1: By selling a plot of land for Rs \: 45000 a person loses 10\% . At what price should he sell it so as to gain 15\% ?

Solution: On selling the plot for Rs \: 45000 , he loses 10\%

\therefore C.P.=S.P. \times \dfrac{100}{100-r}=Rs \: 45000 \times \dfrac{100}{90}= Rs \: 50,000

He now wants a profit of of 15\%

\therefore S.P. = \dfrac{100+r}{100 \times C.P.}= Rs \: (\dfrac{115}{100} \times 50000) = Rs 57,500.

Example 2: A man sells two watches at Rs \: 99 each. On one he gains 10\% and on the other he loses 10\% . What is his gain or loss per cent on the whole transaction ?

Solution: S.P. of the first watch =Rs \: 99 , gain =10\%

C.P. of first watch = \dfrac{S.P. \times 100}{100+r} = Rs \: 99 \times \dfrac{100}{110} = Rs \: 90

Similarly, C.P. of the second watch on which he loses 10\% =\dfrac{S.P. \times 100}{100-r}=Rs. 99 \times \dfrac{100}{90}=Rs \: 110

\therefore total C.P. of the two watches = Rs \: 110 + Rs \: 90 = Rs \: 200

And total S.P. of the two watches = Rs \: 99 + Rs \: 99 = Rs \: 198

\therefore net loss = Rs 2

Loss \% = \dfrac{Loss}{C.P. \times 100}= \dfrac{2}{200 \times 100}= 1\%

Discount

Marked Price: The price printed on an article or on a tag tied to it or the advertised price or the listed price is called the marked price , or, M.P. of the article.

Sometimes to dispose of the old , damaged or perishable goods the retailers offer these goods at reduced prices. The retailers also reduce prices to increase the sale by reducing the marked prices of the articles. The amount deducted from the original marked prices is called ‘Retailer’s discount’ or simply ‘retail discount’ which is generally expressed as per cent or a fraction of the marked or original price.

Net Price (Selling Price): The price of an article after deducting discount from the marked price is called the net price of the article.

NOTE: Discount is always calculated on the marked price.

In solving the problems on discount, the following formula are generally used:

1. S.P. = M.P. - Discount

2. Discount\% = \dfrac{Discount}{M.P. \times 100}

3. If discount is d\% , then,

S.P.= M.P. - Discount

= M.P. - d\% \hspace{1mm} of \hspace{1mm} M.P.

= M.P.-(\dfrac{d}{100} \times M.P.)

=(1-\dfrac{d}{100}) \times M.P.

= (\dfrac{100-d}{100}) \times M.P.

Example 1: The marked price of a pair of shoes is Rs \: 720 . The shopkeeper allows an off season discount of 20\% on it. Calculate – i) the discount and ii) the selling price.

Solution: M.P.= Rs \: 720 and rate \hspace{1mm} of \hspace{1mm} discount = 20\%

i) Discount= 20\% \hspace{1mm} of \hspace{1mm} M.P. = Rs \: (\dfrac{20}{100} \times 720) = Rs \: 144

ii) S.P. = M.P. - Discount =Rs \: 720 -Rs \: 144 =Rs \: 576

Example 2: The marked price of an article is marked 20\% above the C.P. and then it is sold at a discount of 15\% . What is the net gain per cent ?

Solution: Let the C.P. of the article be Rs 100

Marked Price = 20\% more than the C.P. = C.P. + 20\% \hspace{1mm} of \hspace{1mm} C.P. = Rs \: 100 + Rs \: 20 = Rs \: 120

Discount = 15\% \hspace{1mm} of \hspace{1mm} M.P.=Rs \: (\dfrac{15}{100} \times 120) = Rs \: 18

S.P. = M.P. - Discount = Rs \: 120 - Rs \: 18 = Rs \: 102

Profit = S.P. - C.P. = Rs \: 102 - Rs \: 100 = Rs \: 2

Profit\% = \dfrac{Profit}{C.P.} \times 100 = \dfrac{2}{100} \times 100 = 2\%

Exercise

  1. A cloth merchant on selling 33 \hspace{1mm} metres of cloth obtains a profit equal to the selling price of 11 \hspace{1mm} metres of cloth. Find his profit per cent.
  2. An article was sold at a loss of 4\% . Had it been sold for Rs \hspace{1mm} 26 more, there would have been a profit of 9\% . Find the cost price.
  3. A shopkeeper allows 25\% off on the marked price of an article and still gets a profit of 20\% . What is the marked price of the article when it’s cost price is Rs \hspace{1mm} 300 ?
  4. By selling 36 bananas, a vendor loses the selling price of 4 bananas. Find his loss per cent.
  5. A tradesman allows a discount of 5\% on the marked price of goods. How much above the cost price must he mark his goods to make a profit of 14\% ?
« Simple Interest and Compound Interest
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Filed Under: Business Maths Tagged With: Cost Price, Discount, Loss, Marked Price, Net Price, Profit, Sell Price

Comments

  1. gk questions says

    January 20, 2018 at 12:40 am

    Thank you for sharing such valuable info.

    Reply
  2. Roshni says

    June 17, 2020 at 6:23 pm

    Neither gain nor loss condition?

    Reply
  3. Jesse says

    July 30, 2020 at 8:37 am

    Nice enough

    Reply
  4. Anthony says

    August 27, 2020 at 10:00 am

    A farmer buys a cow a farmer for 40000 naira and sells it 33000 naira what is the percentage loss answered his question immediately now now now did you get what I’m saying and send it 2 this email that I am sending you now thanks for using your brain

    Reply
  5. Kamal says

    December 21, 2020 at 1:48 am

    A house is purchased for Rs. 50,00,000. After spending some amount for its maintenance it is sold for Rs 60,50,000 in order to make a profit of 10%, find the maintenance cost.

    Reply

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Table of Content

  • Simple Interest and Compound Interest
  • Profit and Loss
  • Percentages
  • Value Added Tax (VAT)
  • Banking
  • Sales Tax (Trade tax)
  • Shares and Dividends
  • Bills of Exchange
  • Annuities
  • Average Due Date
  • Partnership Business

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